4.9t^2+6t-324=0

Solution for 4.9t^2+6t-324=0 equation:

4.9t^2+6t-324=0

a = 4.9; b = 6; c = -324;
Δ = b2-4ac
Δ = 62-4·4.9·(-324)
Δ = 6386.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{6386.4}}{2*4.9}=\frac{-6-\sqrt{6386.4}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{6386.4}}{2*4.9}=\frac{-6+\sqrt{6386.4}}{9.8}
$